Tournament EV question
I posted this question in the MTT section, but didn't get any answers. Someone suggested that the problem is unsovlvable, but I am not convinced:
In a tournament with equally skilled opponents, the probability of a player finsishing 1st equals his fraction of the chips. But in order to calculate money EV, you need to know a player's probability of finishing in 2nd, 3rd, etc. So how would you calculate these probababilities?
For example, with 4 player left with the following chips fractions (A=.1, B=.2, C=.3, D=.4), what is the probality of each finishing in 2nd, 3rd and 4th?
|