Two Plus Two Older Archives  

Go Back   Two Plus Two Older Archives > General Gambling > Probability
FAQ Community Calendar Today's Posts Search

 
 
Thread Tools Display Modes
Prev Previous Post   Next Post Next
  #1  
Old 10-05-2004, 12:39 AM
Paul2432 Paul2432 is offline
Senior Member
 
Join Date: Jun 2003
Location: Bryn Mawr, PA USA
Posts: 374
Default party poker bad beat rake (puzzle)

Party Poker advertises their bad beat distribution as 70% to the table (with the most to the player badly beaten), 20% to seed the next jackpot, and 10% withheld as Party's fee.

In fact, in the long run party will rake more than 10% of the money taken in by the bad beat rake. Why is this and what is the true long run percentage?

I'll post the solution in a few days if no one comes up with an answer.

Paul
Reply With Quote
 


Posting Rules
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts

BB code is On
Smilies are On
[IMG] code is On
HTML code is Off

Forum Jump


All times are GMT -4. The time now is 02:21 PM.


Powered by vBulletin® Version 3.8.11
Copyright ©2000 - 2024, vBulletin Solutions Inc.