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#1
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Simple grade 12 equation
i need a quick awnser to this
(y^7/4)(1/4y)^1/2(1/8(y^10/8) anyone remeber grade 12 algebra?? |
#2
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Re: Simple grade 12 equation
Write it in a way that's clear and maybe someone could help. Your use of parentheses is very unclear.
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#3
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Re: Simple grade 12 equation
he probably just forgot the last parenthese, but I wish I could help, I forgot how to do that stuff
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#4
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Re: Simple grade 12 equation
(y^7/4) * ((1/4y)^1/2) * (1/8(y^10/8)) 1/4*1/8* y^7/4 *y^1/2 * y ^10/8 1/32 * y^(28/8) |
#5
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Re: Simple grade 12 equation
[ QUOTE ]
(y^7/4) * ((1/4y)^1/2) * (1/8(y^10/8)) 1/4*1/8* y^7/4 *y^1/2 * y ^10/8 1/32 * y^(28/8) [/ QUOTE ] Reduuuuuce! |
#6
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Re: Simple grade 12 equation
You can't factor out the 1/4 because it is also ^1/2. When you factor out the 1/4 it becomes 1/2 when taken outside of the ^1/2.
Answer is: 1/16*((y)^(7/2)) |
#7
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Re: Simple grade 12 equation
[ QUOTE ]
i need a quick awnser to this (y^7/4)(1/4y)^1/2(1/8(y^10/8) anyone remeber grade 12 algebra?? [/ QUOTE ] You probably don't mean what you wrote, but if we add a ')' to the end, and take 1/4y = 1/(4y), then this has a clear meaning by the heirarchy of operations (^,/,*,+,-) which is: (y^7)/4 * 1/(4y)/2 * (1/8)*(y^10)/8 = (y^16)/2048. But if you mean y^(7/4) * [1/(4y)]^(1/2) * (1/8)*y^(10/8) Then that equals (1/16)*y^(5/2) Or if the 1/4y means 1/4 * y, then this is y^(7/4) * (y/4)^(1/2) * (1/8)*y^(10/8) and that equals (1/16)*y^(7/2). In any case, just add the powers of y, and multiply the divisors (after taking a power if necessary). |
#8
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Re: Simple grade 12 equation
i bet this is for a free bigmac or somthing
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