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#1
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Looking for a formula
How do you calculate teh following:
1. How many AK combinations are there when 5 cards are seen none of which are AK. 2. How many AA combinations are there with no cards seen Thanks |
#2
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Re: Looking for a formula
for AK: 4 * 4 = 16 combinations. (ie. Ah can go with any of the four kings, Ac can go with any of the four kings, etc.)
for AA: 4C2 = 4! / 2!2! = 6 combinations. |
#3
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Re: Looking for a formula
thanks
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#4
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Re: Looking for a formula
[ QUOTE ]
1. How many AK combinations are there when 5 cards are seen none of which are AK. [/ QUOTE ] This doesn't change the number of combinations. Are you looking for the odds of having the hand? |
#5
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Re: Looking for a formula
good point, agree. I was making some tables on odds and other measures and I kind of ran two things together. This particular question was getting at an objective way to detemine how to randomly raise 75% of the time. So in the case of AK -- 16 combinations I would raise any time there was no king of clubs in my hand.
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#6
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Re: Looking for a formula
Not to nitpick, but that's not random...that's derived [img]/images/graemlins/grin.gif[/img]
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#7
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Re: Looking for a formula
Well...... it's a non-random, random secletion of an integral part of my digit which gives the the non bias opportunity to rasie with impunity.
So........ |
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