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#1
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Help with some probability situations.
1st:
There are a total of 8 cards in a deck, 2 through 9. There are 8 players at a table. You play 8 hands of high card. You are focusing on 1 specific players cards. What are the chances that that specific player will get a different card each time, and not a repeat in 8 hands? 2nd: There are 8 cards in the deck. 7 Kings and 1 Ace. 8 Players at the table. 8 rounds. You deal 1 card to each player. What are the chances that one specific player will receive the Ace all 8 times? |
#2
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Re: Help with some probability situations.
1st:
P(8,8)/(8^8) = ~.24% ...not overly confident in this, someone please affirm/correct 2nd: (1/8)^8 = 0.00000596% |
#3
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Re: Help with some probability situations.
Thanks, anyone else want to take a stab at this?
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#4
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Re: Help with some probability situations.
I agree with LetYouDown
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#5
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Re: Help with some probability situations.
For the first one, there are 8 cards you can get the first time, 7 cards the second time, 6, and so forth.
So there are 8! ways this can happen. There are 8^8 ways to deal the cards to this player. So .24%. For the second one: 1/8 ^ 8. |
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