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  #1  
Old 07-02-2005, 12:22 PM
obisponator obisponator is offline
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Default Odds question...

Hi guys, I am trying to explain to my friend pot-odds, and I can't give him a good explanation of why when you calculate pot odds, you don't include the chances that someone else at the table either has one of your outs or it was already folded. Can someone give me a quick and easy explanation for why you do not include cards that were dealt to other people to adjust your outs, and please dont say because there is an equally likely chance that they do have the card as if they don't. Thanks.

-Obi-
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  #2  
Old 07-02-2005, 01:21 PM
memphis57 memphis57 is offline
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Default Re: Odds question...

Actually you can make an estimate of the times your opppoonent holds your out, but because you don't know where it is, you get the same answer as using the simplification that all unknown cards are available to you. I.e., assuming 4 outs, 4/47 = (4-odds that he has your outs)/45
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  #3  
Old 07-02-2005, 01:22 PM
Leone Leone is offline
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Default Re: Odds question...

I need information too what is pot odds.
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