|
#1
|
|||
|
|||
Probability of AT LEAST a four flush
Question 1: Are my first 2 assumptions correct given a suited pocket?
Assumption 1: Probability of EXACTLY a four flush on the flop = (C(11,2) * 39) / C(50,3) = .1094 Assumption 2: Probability of EXACTLY a five flush on the flop = C(11,3)/C(50,3) = .0028 Question 2: Do I just sum the above (.1094 + .0028) to arrive at the probability of AT LEAST a four flush on the flop? If not, how would that be computed please? |
#2
|
|||
|
|||
Re: Probability of AT LEAST a four flush
The answer to question 2 is Yes.
|
#3
|
|||
|
|||
Re: Probability of AT LEAST a four flush
Probability of EXACTLY a four flush on the flop = (C(11,2) * 39) / C(50,3) = .1094
Correct Probability of EXACTLY a five flush on the flop = C(11,3)/C(50,3) = .0028 You have the formula correct but you made a mistake on the math, it should be .0084 Question 2: Do I just sum the above (.1094 + .0028) to arrive at the probability of AT LEAST a four flush on the flop? If not, how would that be computed please? That's fine. (.1094 + .0084) = .1178 Lost Wages |
|
|