#1
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small math question <we hope>
I may have asked this BUT if I did I cant find it anywhere and this is the only place this question really belongs and at least I know where to find it now so..........
I was trying to find out something the other day and I had one of those totally foggy days where I actually broke out a deck of cards and STILL wasnt sure I was correct, this was my problem. I want to know just how the formula would be written to show this probability example. What are the odds of me catching 2 spades on the flop if I have the ace and queen of spades on my hand preflop? I was getting 20-1 but it doesnt seen correct so Id like to see it written. Also if I wanted to figure the exact odds of only one spade falling or all 3 how would that be done? I did so well in statistics in school I cant believe my mind is this rotted! : ) Anyone ever check out that "Holdem" odds book, what kinda stuff is in that? |
#2
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Re: small math question <we hope>
There are 11 flush cards and 39 non-flush cards, and there are C(50,3) possible flops ignoring order.
no spades: C(39,3) / C(50,3) = 0.46627551 1 spade: 11*C(39,2) / C(50,3) = 0.415867347 2 spades: C(11,2)*39 / C(50,3) = 0.109438776 3 spades: C(11,3) / C(50,3) = 0.008418367 ----------------------------------------------------------- total = 1 I'll post a review of Petriv's book once I've finished examining it. Here are some earlier comments I have made about it. |
#3
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Re: small math question <we hope>
According to Ken Warren's book I quote:
"The chance of of flopping a four-flush when you are suited is 10.944%. the chance of flopping a four-flush when you are not suited is 2.245%." |
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