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#1
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i just got moved to a new table in a stud tournament. i have played 7 hands and have brought in 7 times, and it's beginning to annoy me. what are the odds of this happening?
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#2
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Assuming 8 to a table, its 1/(8^7) or 0.00004768% of the time.
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#3
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what method did you use to come up with that, just curious
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#4
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the probability of ur hitting the low one time =1/N.
The probility of hitting it 2 times in a row =(1/N)(1/N). The probability of hitting it "K" times in a row where "K" is any integer=(1/N)**K. ***************************** If there were 8 players and u hit the low 7 times in a row,the probability of this happening=(1/8)**7 or (1/8)(1/8)(1/8)(1/8)(1/8)(1/8)(1/8). *************************** If there were 3 players and u hit the low 4 times,the probability of this happening=(1/3)**4 or (1/3)(1/3)(1/3)(1/3 [img]/images/graemlins/smile.gif[/img]). NOTE: There is a probility section on this forum that addresses any mathematical question. There are some excellent mathematicians on this forum who specialize in resolving probablity questions. One excellent mathematician is Bruce. SittingBull |
#5
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While the odds of you bringing it in on the next m hands on an n-handed table are (1/n)^m, the reality is that if you play enough stud, you're going to be the bring-in seven hands in a row at some point. I know I've done it, and I would guess that most of the experienced players here have as well. Not that that's going to make you feel any better about it.
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