#1
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how many possible situations
Here's a modest little question to keep the math people out there occupied.
Assume that players can be categorized in three ways: (1) loose or tight preflop; (2) passive or aggressive preflop; (3) passive or aggressive post-flop. Now consider all the possible starting hand combinations. At a table with six opponents, how many possible situations can arise? And for extra credit, answer the same question at a full, 10 person table. (By the way, I haven't a clue myself.) |
#2
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Re: how many possible situations
There are eight types of players. With n opponents, there are 8^n possible combinations of types, if position matters. That's 262,144 with six opponents and 134,217,728 with nine.
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#3
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Re: how many possible situations
Ok, that's a start. But I was also asking you to take into account all the possible starting hand combinations for the player types too.
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#4
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Re: how many possible situations
Well, there are 169 starting hands. It's true that not all combinations are possible, three players cannot hold AA for example. But it's still pretty close to true that there are 8*169 = 1,352 possible situations per opponent. Raise to the power of the number of opponents. It will be a big number.
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