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Question about Winrate
Ok, if I have a winrate of 1.42BB/100 after 4000 hands, what would you guys say is the range of my true winrate. Like, is it possible that I'm a 3BB/100 player and just have a sample size that is too small?
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#2
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Re: Question about Winrate
You have to provide your standard deviation as well. But this is such a small sample I'd guess the answer is easily yes.
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#3
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Re: Question about Winrate
[ QUOTE ]
You have to provide your standard deviation as well. But this is such a small sample I'd guess the answer is easily yes. [/ QUOTE ] The standard deviation changes from player to player and game to game, but usually not by a huge amount. Let's assume the standard deviation in 100 hands is 15. In 40x100 hands, the standard deviation of the win rate should be about 15/sqrt(40)~2.4. After 4000 hands, your true strength is very likely to be within 2 standard deviations, 1.4+-4.7 BB/100. That's not a very tight estimate. It is hard to conclude anything from only 4000 hands. |
#4
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Re: Question about Winrate
[ QUOTE ]
The standard deviation changes from player to player and game to game, but usually not by a huge amount. [/ QUOTE ] If we're talking about "good" players, I would probably agree. But a weak-tight player, or a LAG, or perhaps anyone with a true winrate that is negative, could likely have a standard deviation that differs significantly from the "norm". I just wanted to mention this because the OP might be trying to decide if he's a "good" player. And, it seems to me, the assumption of a 15BB/100 SD presupposes this fact to some degree. |
#5
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Re: Question about Winrate
how do I find out my standard deviation?
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#6
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Re: Question about Winrate
[ QUOTE ]
how do I find out my standard deviation? [/ QUOTE ] If you have PokerTracker, it's under "Session Notes" tab -> "More Detail..." button |
#7
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Re: Question about Winrate
ah cool. So say I know my current winrate after a small sample size of hands and my standard deviation. How can I find out the range of my true winrate?
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#8
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Re: Question about Winrate
How much is large enough sample size to draw a conclusion on if you are or aren't a winning player at a certain limit (on let's say 97% certainty).
Is it 50k+ hands, 100k+ hands? I currently have 29,138 hands of $2/4, BB/100 of 3.52, SD/100 of 15.2394. I'm pretty certain I'm a winner, since I've been playing and winning for quite a long time. Those are just since I recently started logging with PT. But so, how much is enough when speaking of sample size? /ode |
#9
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Re: Question about Winrate
[ QUOTE ]
ah cool. So say I know my current winrate after a small sample size of hands and my standard deviation. How can I find out the range of my true winrate? [/ QUOTE ] pzhon showed the idea above. The interval WR +/- 2*SE will include your true win rate with 95.4% confidence, where SE= SD/sqrt(N), SD and WR are in BB/100, and N= #hands (in hundreds) The factor 2 can be varied depending on the desired confidence: 1 -> 68% confidence 1.96 -> 95% confidence 3 -> 99.7% confidence The greater the desired confidence, the wider the interval. |
#10
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Re: Question about Winrate
[ QUOTE ]
How much is large enough sample size to draw a conclusion on if you are or aren't a winning player at a certain limit (on let's say 97% certainty). Is it 50k+ hands, 100k+ hands? [/ QUOTE ] Whether or not you are a winning player depends on WR, SD, and N (#hands). Calculate the quantity WR/(SD/sqrt(N)) This is the distance from breakeven in # of SD. For >= 97% confidence, this quantity >= 2.17. [ QUOTE ] I currently have 29,138 hands of $2/4, BB/100 of 3.52, SD/100 of 15.2394. I'm pretty certain I'm a winner, since I've been playing and winning for quite a long time. Those are just since I recently started logging with PT. But so, how much is enough when speaking of sample size? [/ QUOTE ] It's relative, but 3.52/(15.2/sqrt(291))=3.95 so you can be better than 99.9% confident you are a winning player. |
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