Two Plus Two Older Archives  

Go Back   Two Plus Two Older Archives > General Gambling > Probability
FAQ Community Calendar Today's Posts Search

Reply
 
Thread Tools Display Modes
  #1  
Old 12-14-2005, 10:30 PM
Guest
 
Posts: n/a
Default QJ argument

A friend and I are having a small argument over this. I said that if I have QJ against 2 opponents, that there is the following chance that one of them has an A or a K.

(42/50)*(41/49)*(40/48)*(39/47)=48.6% or 51.4% that someone will have an A or a K.

However, he thinks it's much lower. Are my calculations correct?
Reply With Quote
  #2  
Old 12-14-2005, 10:49 PM
ohnonotthat ohnonotthat is offline
Senior Member
 
Join Date: Aug 2005
Location: New Jersey - near A.C.
Posts: 511
Default Re: QJ argument

Your calculations are perfect.

Remember though that even if an Ace AND a King flop the chance of one of these two opponents having flopped a pair goes down and is now 43.22%

1 - (41/47 x 40/46 x 39/45 x 38/44) x 100

*
Reply With Quote
Reply


Posting Rules
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts

BB code is On
Smilies are On
[IMG] code is On
HTML code is Off

Forum Jump


All times are GMT -4. The time now is 03:14 PM.


Powered by vBulletin® Version 3.8.11
Copyright ©2000 - 2024, vBulletin Solutions Inc.