#1
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Odds of higher PP in 6-max game...
What are the odds of at least 1 higher PP being dealt in a 6-handed game for the following hands...
KK,QQ,JJ, If this has discussed here before then can someone please point me in the right direction to the thread -- I came up empty... |
#2
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Re: Odds of higher PP in 6-max game...
[ QUOTE ]
What are the odds of at least 1 higher PP being dealt in a 6-handed game for the following hands... KK,QQ,JJ, If this has discussed here before then can someone please point me in the right direction to the thread -- I came up empty... [/ QUOTE ] If you had just searched for KK or QQ, you would have found this post of a few days ago that answers those two cases. Now for AA or KK or QQ vs. JJ (6 handed): 5*18/C(50,2) - C(5,2)*18*13/C(50,2)/C(48,2) + C(5,3)*18*(12*8 + 1*12)/C(50,2)/C(48,2)/C(46,2) =~ 7.18% or 12.9-to-1. The exact expression would have 5 terms since all 5 opponents could have these hands. These 3 terms are accurate to better than 0.00001%. |
#3
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Re: Odds of higher PP in 6-max game...
Wow people must really drive you nuts on here [img]/images/graemlins/smile.gif[/img]
Thanks you so much for your help, im new here, but its seem you are a great asset to the forums. I'll work on my searching... |
#4
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Re: Odds of higher PP in 6-max game...
What does the term "C(50,2)/C(48,2)" represent, and what does "12*8 + 1*12" represent?
thanks |
#5
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Re: Odds of higher PP in 6-max game...
[ QUOTE ]
What does the term "C(50,2)/C(48,2)" represent, and what does "12*8 + 1*12" represent? thanks [/ QUOTE ] The total number of ways to deal hands to 2 opponents with 50 cards, including order, is C(50,2)*C(48,2), so we divide by this amount. The number of ways that 3 opponents can hold 3 pairs AA-QQ is 18*(12*8 + 1*12). After the first opponent gets one of the 18 pairs, the second opponent has 12 ways to pick one of the other 2 pairs, or 1 of the same pair. If he gets one of the 12, that would leave 8 ways for the third player to choose a pair (6+1+1). If he chooses the 1 pair, that leaves 12 ways for the the third opponent to choose a pair (6 + 6). |
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