#1
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4 flush on board, 5 players, no one has the flush--what are the odds?
SSIA.
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#2
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Re: 4 flush on board, 5 players, no one has the flush--what are the odds?
On river, assuming random hands:
C(38,10) / C(47,10) = 9.1%. |
#3
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Re: 4 flush on board, 5 players, no one has the flush--what are the odds?
[ QUOTE ]
On river, assuming random hands: C(38,10) / C(47,10) = 9.1%. [/ QUOTE ] I'm still trying to relearn this combination thing (helps me to verbalize). C(38,10) --> Number of possible combinations of 10 cards out of 38. This is the 39 non-flush cards - the non-flush card on the board = 38. 10 cards dealt to 5 players. C(47,10) --> Number of combinations of hole cards for 5 players from the rest of the deck (less board). If you are one of the players, and posses no flush cards, then it changes to: C(36,8)/C(45,8)? 14%? Is this correct? |
#4
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Re: 4 flush on board, 5 players, no one has the flush--what are the odds?
Is this correct?
yes |
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