#1
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7 stud probability question
I was looking at another site and I can't come up with these numbers. The site reports the following percentages and odds, but I just cannot figue out the math for this situation.
The site says if You Have 10c - Jc - Qc: The probability that the final strength of your hand after seven cards will be... <font class="small">Code:</font><hr /><pre>(Hand) (%) (odds) Str. Fl. 1.49 66.2 to 1 Flush 16.56 5.04 to 1 Straight 14.91 5.71 to 1 </pre><hr /> I don't really care about the math for the Straight Flush split out from the Straight and Flush, although I guess that's necessary so that you don't count the straigh flush as both a straight and a flush? Any way, can someone show the math that was used to get these numbers? |
#2
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Re: 7 stud probability question
Too hard?
Or too boring? |
#3
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Re: 7 stud probability question
[ QUOTE ]
Too hard? Or too boring? [/ QUOTE ] stuff like this has been just been done many times. here's how get the chance of a flush or str8 flush. You need to get 2, 3, or 4 clubs out of the next 4 cards. There are 9 clubs left. (10 choose 4) ways to get 4 more clubs. (10 choose 3)*39 ways to get 3. (10 choose 2)*(39 choose 2) ways to get 2. There are 49 choose 4 ways to draw the next 4 cards, in total. Thus the chance we want is: ((10 choose 4) + (10 choose 3)*39 + (10 choose 2)*(39 choose 2)) / (49 choose 4) = 0.180459325 which agrees with sum of the flush and str8 flush chances that you posted. I'm bored. gm |
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