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Roulette 3 Sigma
Hi! [img]/images/graemlins/confused.gif[/img]
Could anybody please tell me, what's 3-Sigma at roulette, when you always only play one number at a time? Best regards Dai |
#2
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Re: Roulette 3 Sigma
[ QUOTE ]
Hi! [img]/images/graemlins/confused.gif[/img] Could anybody please tell me, what's 3-Sigma at roulette, when you always only play one number at a time? Best regards Dai [/ QUOTE ] 3-sigma for your losses, or 3-sigma for a particular number coming up more often than it should? Also, single 0 or double 0? |
#3
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Re: Roulette 3 Sigma
Hi BruceZ: Ah, ok, I will be more specific: 3-sigma for a special number to come up at a single 0-Wheel (37 numbers, europe). The question I ask myself is: If I always play, let's say, the 7, then how many jetons do I have to win with it to be sure it's coming more often than random. (I think the analogon in poker is: Win 300 BB to prove you're a winning player at a given level, isn't it?!)
Best regards Dai |
#4
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Re: Roulette 3 Sigma
Hi!
Anybody still looking for an answer? Help really would be appreciated. regards Dai [img]/images/graemlins/confused.gif[/img] |
#5
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Re: Roulette 3 Sigma
If you are interested in testing whether the zero comes up more often than a different numer you shouldn't test on the variance. Let P7 be the probability of a 7 in a random round of roulette. Than you have zero hypothesis H_0: P7 = 1/37 versus H1: P7 > 1/37. This can be tested with a standard test on sample average. This would make more sense than testing the variance.
The latter would be possible however. In this case you need the variance of a uniform distribution on 0,...,n. I'm suprised you didn't google it up, but it is (n^2+2n)/12. Now you could do a ratio test o something, out of my head, I suppose you should use an $F$ statistic. However, don't bother. Your roulette game is fair. |
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