#1
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Inclusion - exclusion. Specific example
Hi all,
My question is very specific and concerning an archived thread with BruceZ in the drivers seat: http://archiveserver.twoplustwo.com/...art=1&vc=1 In Brucez's answer it follows: " C(8,2)* 78/C(52,2) * 73/C(50,2) = 9.8%. C(8,2) is the number of ways to pick the 2 players. There are 73 pairs remaining after the first player chooses a pair" - Now, why are there 73 pairs left after 1st player chooses a pair? I know we can't just pick from 12 ranks and pretend that the 2nd player can't pick a pair of the same rank as the first. But why 73...? I want of course to be able to make the next term myself. ty. |
#2
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Re: Inclusion - exclusion. Specific example
Because there are 12 ranks remaining where there are 6 ways to choose a pocket pair...C(4,2), and one rank remaining where there's only one way to choose the pair (only two cards left). C(12,1) * C(4,2) + C(2,2) = 73.
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#3
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Re: Inclusion - exclusion. Specific example
Ahhh. of course.
thanks |
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