Is this easy to do?

[stokken]

There has been alot of posts about AA vs KK and the likes.
I have searched, but not found quite what I am looking for.

And what I am looking for is maybe a bit extensive?

The probability for a spesific PP is 1/52 x 3/51 and if 9 handed you multiply by 9 for the likelyhood that one hand contains this spesific pair.Since there are 9 occasions for this particular event to take place.
How do u go about calculatng the probability of running into an overpair given your hand is XX and n is the number of possible overpairs( with this I am thinking along this line I have JJ, n=3) and m is the number of opponents yet to act?