#1
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Getting out-tripped
What are the odds that you're holding a pocket pair and someone else at the table is also holding a pocket pair and both of you hit your trips on the flop? I've had this happen twice in the past 24 hours, so I was just curious what the odds are on it happening.
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#2
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Re: Getting out-tripped
Here is a rough estimate.
If you have n opponents and you hold a pair, then the expected number of opponents with pocket pairs is n*( (1+12*6)/C[50,2]) ~= n*0.06. If you and one opponent both have pairs, then the probability that both of you will hit trips is 2*2*44/C[48,3] ~= 0.01. So the probabilty that someone else hit trips when you hit trips with your pair is about n*.059*0.01 = n*0.0006 or about n/1650. |
#3
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Re: Getting out-tripped
So the probabilty that someone else hit trips when you hit trips with your pair is about
n*.059*0.01 = n*0.0006 or about n/1650. While that is strictly speaking what he asked for, that is not such a relevant number. The more important number would be how often an opponent will have a set GIVEN that you have already flopped a set. |
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