Re: Possible hands in detail + the chances of getting \"no cards\"
Perhaps someone with more time/skill than me could produce a formula to work out the chance of getting AA/KK/QQ or JJ x times in y deals???
By the binomial distribution, the probability of exactly x in y deals is:
C(y,x)*(24/1326)^x*(1 - 24/1326)^(y-x)
For at least x in y deals, use binomdist in Excel to compute the probability of at most x-1, and subtract this from 1.
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