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Old 12-29-2005, 07:45 PM
AaronBrown AaronBrown is offline
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Join Date: May 2005
Location: New York
Posts: 505
Default Re: probability of getting flush with suited hand

ChicagoVince's method works pretty well, here is the exact way to do it. You have to figure the cases of getting exactly three, four and five suited cards separately.

Three suited cards: C(11,3)*C(39,2) = 122,265
Four suited cards: C(11,4)*C(39,1) = 12,870
Five suited cards: C(11,5)*C(39,0)= 462

To get the probabilities, you have to divide by C(50,5) = 2,118,760. You get 5.77%, 0.61% and 0.02% respectively, for a total probability of 6.40%.
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