Re: Riddle -- Probability of Expectation
This is such an easy problem.
Work with one line only: if we know the probability for one line, we are done.
Let A, B be the probability of "hues", "hews" occuring in that line. P(A union B) = P(A) + P(B) - P(A intersection B)
where all of them are easy to calculate.
Here I haven't actually calculated anything, but it is very easy to do, and requires only grade 11 math.
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