Re: Probability: Three-flush to Flush
Ok I think I understand where I screwed up, and I understand how you calculated the probability of making the runner-runner flush. If I wanted to express that as odds, how would I do so? I can't just take the reciprocal of 0.0416 to get 24:1 right?
You mentioned 9/(37 + 9) probability is equivalent to 37:9 odds... so the reciprocal wouldn't work. How do I get from one to the other? (Or better yet, how do I calculate the runner runner in terms of odds as opposed to probability?)
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