[Bozeman]

Ok, I will assume that each letter is a unique digit. If I find a solution with this assumption, good, if not, I will relax the assumption.

D=5, therefore T=0, and R>5. Also, L+L+1=R or R+10, so R is odd. From the second digit, and the fact that 0 is already taken, we know that E=1 or 9. If it is 1, then A=5, but T=5, so thus E=9 and A=4 (A+A=E or E-1). Therefore R=7, and R+10=L+L+1, so L=8. The Third digit tells us that N+7=10+B, so N=B+3. The only available choices are N=6, B=3. This leaves G and O. D+G+1=R, so G=1, therefore O=2. (note: no constraint is applied to O by the second digit).

In summary:
T=0
G=1
O=2
B=3
A=4
D=5
N=6
R=7
L=8
E=9

and 526485+197485=723970.

Craig