Re: Odds of winning vs. a random hand
[ QUOTE ]
Thanks but I am a little more concerned about how I would go about doing the actual math behind it rather then just the pure percent result from pokerstove.
[/ QUOTE ]
Well, there are 1035 hands the other player could have. Just run through each one and see how many rivers result in a win for K-J vs. the random hand and do a sum of both, then divide. Or get PokerStove.
|