Re: How do i figure this out?
no. in both cases we are simply counting how many hands fulfill the given criteria, regardless of order...
so, the number of possible two-[img]/forums/images/icons/heart.gif[/img] combinations from the 11 remaining [img]/forums/images/icons/heart.gif[/img]s is (11 choose 2), which is 11 * 10 = 110.
since a flop is three cards, there are 39 possible ways that each of those combinations could come with a non-[img]/forums/images/icons/heart.gif[/img] as the third card, or 48 ways that the card could come, with or without a [img]/forums/images/icons/heart.gif[/img]. this is regardless of order, this only speaks to the actual combination of cards, so the count is (110 * 39) or (110 * 48), depending on whether you want to count flopped flushes. 6[img]/forums/images/icons/heart.gif[/img]3[img]/forums/images/icons/heart.gif[/img]K[img]/forums/images/icons/spade.gif[/img] and K[img]/forums/images/icons/spade.gif[/img]6[img]/forums/images/icons/heart.gif[/img]3[img]/forums/images/icons/heart.gif[/img] are only one combination, and should only be counted once.
-switters
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