Re: KQo Dominated?
There are 1326 combinations of Texas hold'em hole cards, 50!/(48!*2!)= C(50,2).
AK= 4*3 combinations
AQ= 4*3
AA= 6
KK= 3
QQ= 3
for a total of 36 combinations. So the odds someone dominating your hand is 36/1326= 2.71%
At a 10 person table the odds that no one has a dominating hand is (1-.0271)^9= 78.1% At a 6 person table (1-.0271)^5= 87.1%.
Hope this helps.
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