Re: Probability of one OR more person getting dealt hands XX-YY
vqchuang,
The correct answer is somewhat complicated but here is an approximation:
if
X=number of hands that call me (it would be something out of 1225)
Y=number of players still to act behind me
Z=probability of someone (one or more) getting a hand that calls me.
Z ~= (1- (1- X/1225)^Y).
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