Math?
It's been a while since I took probability but I believe the odds of a single player having a flush AFTER we know a monotone flop has dropped are calculated thus:
10 cards of that suit remain unseen. 47 cards remain unseen in total. Odds of player having 1 spade is 10/47 and of having second spade 9/46. Odds of having 2 spades is 10/47 * 9/46 or 1/24. This is almost 5 times higher probability than 1/119.
Did I remember my HS math correctly?
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