[LetYouDown]

Corrected (I hope):

Say one player holds 5-5 the other 10-10. The probability of the flop coming 5-10-X where X is not a 5 or a 10:

(C(2,1) * C(2,1) * C(44,1))/C(48,3)

176/17296 = 1.02%

Say one player holds 5-5, another 10-10 and another Q-Q. The probability that 2/3 will flop a set is:

5-10-X where X is not a 5, 10 or Q = (C(2,1) * C(2,1) * C(40,1))/C(46,3) = 160/15180 = 1.05%
5-Q-X where X is not a 5, 10 or Q = 1.05%
10-Q-X where X is not a 5, 10 or Q = 1.05%

So for 2 out of 3 flopping a set, I get 480/15180 or about 3.16%%.

For all three flopping a set, I get 8/C(46,3) or .053%.

This seem right now or am I still fubaring it?