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Probability question...
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04-30-2005, 11:58 PM
jason1990
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Join Date: Sep 2004
Posts: 205
Re: Probability question...
You could get away with a single integral here, if I'm interpreting the assumptions right:
P(A<B,A<C,A<D)=E[P(A<B,A<C,A<D | A)]=E[f(A)]
f(x)=P(x<B)P(x<C)P(x<D)
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