[BruceZ]

[ QUOTE ]
i need a quick awnser to this

(y^7/4)(1/4y)^1/2(1/8(y^10/8)

anyone remeber grade 12 algebra??

[/ QUOTE ]

You probably don't mean what you wrote, but if we add a ')' to the end, and take 1/4y = 1/(4y), then this has a clear meaning by the heirarchy of operations (^,/,*,+,-) which is:

(y^7)/4 * 1/(4y)/2 * (1/8)*(y^10)/8

= (y^16)/2048.


But if you mean

y^(7/4) * [1/(4y)]^(1/2) * (1/8)*y^(10/8)

Then that equals (1/16)*y^(5/2)


Or if the 1/4y means 1/4 * y, then this is

y^(7/4) * (y/4)^(1/2) * (1/8)*y^(10/8)

and that equals (1/16)*y^(7/2).


In any case, just add the powers of y, and multiply the divisors (after taking a power if necessary).