5 players see a flop (Hold\'em)...
5 players see a flop. The flop has 2 spades. What is the probability that at least one of the 5 players holds 2 spades?
Chance of 1 player holding 2 spades is 5,09% (easy), but already by the 2nd players the calculations becomes tough, since you have to account for a possible spade in previous players hand.
I can't think of a clever way to calculate this.
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