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Old 04-11-2005, 02:35 PM
Paul2432 Paul2432 is offline
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Join Date: Jun 2003
Location: Bryn Mawr, PA USA
Posts: 374
Default Re: # of Omaha Starting hands

Your post contains several errors.

It is entirely coincidence that 13 x 13 = 169 = number of starting hands in hold'em.

The proper way to count hold'em starting hands is

Pairs = 13
Unpaired = 12+11+10+9+8+7+6+5+4+3+2+1 = 78
(this represents Ace + 12 lower ranked cards. King + 11 lower ranked cards . . .)

Unpaired hands can be suited or offsuit so total hands is equal to 78 + 78 + 13 = 169.

In order to count Omaha hands you would need to count separately quads, trips, two pair, one pair and no pair hands. Your method double (or more) counts many hands. For example, AAA3 would be counted four times (AAA3,AA3A, A3AA, and 3AAA).

Paul
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