Re: Probability question...
Conditioned on A, those events are independent. In general, if
f(x) = P(A<B,A<C,A<D | A=x),
then
P(A<B,A<C,A<D) = E[f(A)].
In this case, since everything is independent, we have
f(x) = P(x<B,x<C,x<D) = P(x<B)P(x<C)P(x<D).
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