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Old 03-16-2005, 01:05 AM
dabluebery dabluebery is offline
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Join Date: Dec 2003
Posts: 13
Default Re: A very simple problem

It's late, and I wish I was drunk so I'd have more excuses for not thinking clearly, but I'm definitely neither drunk nor thinking clearly. Damn.

I think you're answering a question he didn't ask. I answered his question the most simple way I could. I could do different math, so you'd understand where I'm coming from, and what question I'm answering.

Probability of getting the ace of spades (for example) in two consecutive hands is done like this;

The probability of NOT getting the ace of spades in hand one is as follows;

when you draw the first card, 51 of 52 times it's not the ace of spades. when you draw the second card, 50 of 51 times it's not the ace of spades. So the probability of not getting the ace of spades is;

(51/52) * (50/51), which is = 25/26. Since the probability of NOT getting the ace of spades is 25/26, the probability of getting it is 1/26.

Rinse, repeat. Two times in a row = (1/26) * (1/26) = 1/676

Again, this kind of math gets kinda tedious, and you may as well learn the combination math anyway, but it's not for everyone.

Can I go to bed now?

Rob
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