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Old 08-02-2002, 07:16 PM
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Default ACK--work in progress above, errors



Thaty wasn't supposed to be posted, I was still working on it and se an error already.


6^5 = total number of combinations given one toss. For each of the 5 slots the 3 can fall into, the other slots together hold 5^4 combos. So we have 5(5^4)/6^5 giving the fraction of ways a 3 will fall on one toss.


The total combos given 5 tosses are 6^5^5.


That's how far I am now but I keep getting disconnected and its time for poker



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