Re: Random number between 1 and 100
If you are willing to take the median instead of the average (mean), the problem is much easier. The median is exp[ln(0.5)/9]*100 = 92.59. Substitute 8 for 9 and you get the answer for batches of 8. In this case the mean is lower than the median because it's possible to get a batch with a much lower maximum, but you can't get one higher than 100.
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