Re: What is the relation between pot odds and probability here?
Major Kong - I like your answer.
Here's another way for the non-algebra minded.
"You bet $110 to win 100. What percentage of the time must you win the bet to break even including the vig?"
Shattered - Maybe you can intuitively see that if you play twenty one times, winning eleven and losing ten, you will break even.
That is, $110*10 = $100*11. (I don't know if that's obvious to you or not.
If it is, you can see that you need to win 11 times out of 21.
If you want the answer in terms of percentages, 11/21 = 0.5238, so that 52.38% is how much you must win (leaving 47.62% for losing). It's the same answer as Major Kong, but less elegant.
I think you have to either set up an algeraic equation or somehow intuitively see an equivalency relationship, whatever works best for you.
Buzz
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