[Cobra]

LetyouDown,

I believe you have a couple of errors.

(C(3,1) * C(3,1) * C(44,1))/C(48,3)

Should be C(2,1)*c(2,1)*44/c(48,3) = 1.02%

The probability of two people getting exactly two sets if three people have pairs and see the flop is:

C(3,2)*c(2,1)*c(2,1)*40/C(46,3) = 3.16% That is three ranks choose two, each rank has two cards choose one, and there are 40 misses.

Cobra