Re: Odds for turning a pair into a set
This should go in the probability forum.
2 outs, 5 cards to come (ignores straights/flushes/opponent redraws, etc)
The calculation is quite simple. 50 unknown cards, 2 of which help us. So 1 - (48/50 * 47/49 * 46/48 * 45/47 * 44/46), which gives us a ~19.2% chance of happening. 4.2:1 or so.
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