Re: Basic Suited Connectors question.
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I get 66 exactly-trips combos
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I'm wondering how you got there. Did you consider the fact that there's 3 ways for the first two cards to be J-J? Maybe I'm overlooking something. Wouldn't surprise me.
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No. My mistake. I multiplied by 11, for the remaining
non-trip-contributing card, and forgot about its suit.
I should have multiplied by 44. (Note 66x4 = 264).
Apologies.
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