Re: How would you calc probability of opponents hands?
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3 ways / c(50,2)
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This is completely wrong. Given the flop (and not knowing our own cards, since the OP did not give them) there are 48 unseen cards left. 45 of them are non-jack cards. We'll calculate the probability that no oppo has a J, and then subtract it from 1 to determine the chance that at least one oppo has either a pair or a set of jacks:
1 - ((45 choose 2)/(48 choose 2))*((43 choose 2)/(46 choose 2))*((41 choose 2)/(44 choose 2))= .3362
So there is about a 34% chance that at least one of your oppo's has at least one jack.
Maybe I'll do the others later.
gm
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