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All you have to do is find the probability of getting KK and square it because the hands are independent. ((4/52)*(3/51))^2= .00002047460125 or 48841 to 1. I think I did the math correctly.

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Not that its very important, but I think yours is for any one person getting dealt KK twice in a row. Since all 4 K's are dealt to someone at the table here's an approximation...
1st KK dealt to someone at table = (4/52)*(3/51)*10 = 1/22.1
2nd KK dealt to another at table = (2/50)*(1/49)*9 = 1/136
happens 2 times in a row = [(1/22.1)*(1/136)]^2 = 1/9,033,631 = alot of poker before you see it again...