If we bet on Red in Roulette. The chances of us losing on a North America (double greens) is abt 0.5263.

The chance of 10 losers in a row is 0.5263^10 or 0.163%

0.163% is about 1 in 650. So in the long run about every 650 rounds of 10 will get a 10 losers in a row. 99.837% of the time u'll get a mixture of wins + losses.

The funny thing is...i wrote a Red/Black/Green simulator and 10 in a row seems to appear far more often! Like 1 in 20/30 rounds or something!! [img]/images/graemlins/shocked.gif[/img]