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Any Q or any 7 beat you, so 8 of the 45 cards you can't see can't be in any of the three hands if you're good. The probability that nobody has a straight is therefore

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That cant be right. You say its 8 of 45 unseen that beats him. If so then there would be one less unseen card when we calculate the probability of our opponent getting an X card (which is 100% [img]/images/graemlins/smile.gif[/img] ), 44 unseen cards. 46 cards of the 44 unseen cards gives him any card (the X-card). Even though we dont remove one from the unseen cards he still has a 46/45 chance of getting ANY card. You cant be more than 100% sure to get a second card. [img]/images/graemlins/tongue.gif[/img]

Im thinking there is 8 of 47 unseen cards that gives one opponent a straight. And 46 of 46 unseen cards that gives him any kicker.