Thread: probability to be beat here?
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Old 09-01-2005, 02:07 PM
LetYouDown LetYouDown is offline
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Join Date: Mar 2005
Location: Sharing a smoke w/negativity
Posts: 524
Default Re: probability to be beat here?
There's 45 cards left, we're aware of 7.

C(37,6)/C(45,6) = 28.54%

Edit: I tried to rattle this out with inclusion/exclusion and I came to losing 83.25% of the time. Here's to hoping BruceZ can assault this problem.
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