Re: A pair in the flop
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So it should be 13*6*48/(52 choose 3) = .1694
The "c" or choose is confusing to me. I understand +-/* but not choose. Can you explain the process?
Also, since the percentage is .1694 that translates to about a 5.9/1 dog. Meaning one in 6 flops will probably contain a pair. If that is true, I have indeed learned something.
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52 choose 3 represents the number of ways you can choose 3 cards (the flop) from 52 cards (the entire deck). Order does NOT matter, i.e. A,2,3 is the same as 3,A,2
The calculation for this is 52!/(3!*(52-3)!)
Note: 52! = 52*51*50*...*1
3! = 3*2*1
(52-3)! = 49! = 49*48*47*46*...*1
If you write down the numbers, you see that most of them cancel out.
That is: 52!/(3!*(52-3)!) =
(52*51*50)/(3*2) = 22,100
Hope that helps.
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