[GFunk911]

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There are 1326 possible preflop hands. There are roughly 1326^2 total preflop matchups (some of which are invalid because they share a card).

There are then roughly 1.7M entries in a full win/lose/tie matchup matrix.

Clearly some of these are equivalent. For example, AhTs vs. KhTs has exactly the same w/l/t breakdown as AcTh vs. KcTh, because both the rank and suit relationships are the same.

Q1: How many unique showdown probabilities are there for every possible two-hand matchup?

eastbay

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Is this what you're looking for. Here it is only for when both sides are suited

There are 78 different ABs hands you can make.
If Player A has ABs, Player B can only make 55 different suited hands of the same suit.

78 (ABs v CDs where suits are different) + 55 (ABs v CDs where suits are same). = 133 different probabilities for suited v suited.

Obviously there are many 50%'s (KTs v KTs, KJs v KJs, etc) bt they are really different probabilities. I assume you want them seperate.

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Right, I'm interested in full w/l/t values, not just "pot equity". So KhTh vs. KsTs is not quite the same as KhJh vs. KsJs, for example. It is possible that there are "coincidental" non-unique probabilities in there somewhere. I'm not interested in figuring out what those might be.

My answer is over 100k, btw, just to give an idea.

eastbay

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Yes, i had a total brain fart and said 78+55, instead of (78+55)*78. I already FMP.