Thread: Probability of the dealer having the same up card in BJ
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Old 11-16-2002, 12:35 AM
BruceZ BruceZ is offline
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Default Re: Probability of the dealer having the same up card in BJ
sum[k=7,10]C(10,k)*(1/52)^k*(51/52)^(10-k) = 1.1 x 10^-10
= 1 in 9 billion (American billion).
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